In List§
See primary documentation in context for routine permutations
multi permutations(Int() --> Seq)multi permutations(Iterable --> Seq)multi method permutations(List: --> Seq)
Returns all possible permutations of a list as a Seq
of lists:
.say for <a b c>.permutations;# OUTPUT:# (a b c)# (a c b)# (b a c)# (b c a)# (c a b)# (c b a)
permutations
treats all elements as unique, thus (1, 1, 2).permutations
returns a list of 6 elements, even though there are only three distinct permutations, due to first two elements being the same.
The subroutine form behaves the same as the method form, computing permutations from its first argument $from
. If $from
is not an Iterable
, coerces $from
to an Int
and picks from a Range
constructed with 0..^$from
:
.say for permutations 3;# OUTPUT:# (0 1 2)# (0 2 1)# (1 0 2)# (1 2 0)# (2 0 1)# (2 1 0)
In Any§
See primary documentation in context for method permutations
method permutations(|c)
Coerces the invocant to a list
by applying its .list
method and uses List.permutations
on it.
say <a b c>.permutations;# OUTPUT: «((a b c) (a c b) (b a c) (b c a) (c a b) (c b a))»say set(1,2).permutations;# OUTPUT: «((2 => True 1 => True) (1 => True 2 => True))»
Permutations of data structures with a single or no element will return a list containing an empty list or a list with a single element.
say 1.permutations; # OUTPUT: «((1))»